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4·2^x=2·3^x

 Jan 27, 2016
 #1
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4·2^x=2·3^x

  -2x       -2x

------------------

4=2 -1x

-2    -2

---------------

2=1x

 

x=2

 Jan 27, 2016
 #2
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4 * 2^x = 2 * 3^x   DIvide both sides by 2

2 * 2^x = 3^x         Take Log of both side

xLog2+Log2    = x log3

 

.301x +.301 = .477x

.301 = .1761x

x = 1.709                   I think !

 Jan 27, 2016
 #3
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Thanks!

 Jan 27, 2016

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