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if x,y,z are positive numbers, prove thet :
1/logx(xyz) + 1/logy(xyz) + 1/logz(xyz) = 1
 Sep 10, 2013
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First you have to use the Change of Base Formula. Hence, log_x(xyz)=ln(xyz)/ln(x), etc.
Then, your equation becomes,

ln(x)/ln(xyz)+ln(y)/ln(xyz)+ln(z)/ln(xyz)=(ln(x)+ln(y)+ln(z))/ln(xyz)=ln(xyz)/ln(xyz)=1

Since, we have the same denominator we can combine everything in a single fraction then using properties of log we get the final answer.
 Sep 10, 2013

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