3x-3/x-2=x(x-1)
3x-(3/x)-2=x(x-1)
first recognise that x cannot equa 0
then multiply through by x to get rid of the fraction
then take it all to one side and put equal to 0
I think you get
0=x^3 - 4x^2 +2x +3
If f(x) = x^3 - 4x^2 +2x +3 then
f(3) = 27-36+6+3 = 0 therefore (x-3) is a factor
Do an algebraic division to get the other factor and it is (x^2 - x - 1)
so
=> 0=(x-3) (x^2 - x - 1)
One root is 3 and the other is the zeros of x^2 - x - 1 which you can find using the quadratic formula or by completing the square method. (There are a total of 3 roots)
+118654 
