What is the probability that a point chosen inside the largest rectangle is not within a shaded region?
We first need to find the area of the shaded region.
The width is 3 + 1 + 2 = 6
The length is 2 * 5 = 10
The total area of this rectangle is 6 * 10 = 60
The shaded region has a total area of:
3 * 2 + 2 * 2 + 2 * 1 = 12
The part of the rectangle that is not shaded must be 60 - 12 = 48
The probabilty is 48/60 = 4/5 = 0.8 = 80%
We first need to find the area of the shaded region.
The width is 3 + 1 + 2 = 6
The length is 2 * 5 = 10
The total area of this rectangle is 6 * 10 = 60
The shaded region has a total area of:
3 * 2 + 2 * 2 + 2 * 1 = 12
The part of the rectangle that is not shaded must be 60 - 12 = 48
The probabilty is 48/60 = 4/5 = 0.8 = 80%