What is the probability that a point chosen inside the largest rectangle is not within a shaded region?

wiskdls Apr 15, 2018

#1**+3 **

We first need to find the area of the shaded region.

The width is 3 + 1 + 2 = 6

The length is 2 * 5 = 10

The total area of this rectangle is 6 * 10 = 60

The shaded region has a total area of:

3 * 2 + 2 * 2 + 2 * 1 = 12

The part of the rectangle that is not shaded must be 60 - 12 = 48

The probabilty is 48/60 = 4/5 = 0.8 = 80%

GYanggg Apr 15, 2018

#1**+3 **

Best Answer

We first need to find the area of the shaded region.

The width is 3 + 1 + 2 = 6

The length is 2 * 5 = 10

The total area of this rectangle is 6 * 10 = 60

The shaded region has a total area of:

3 * 2 + 2 * 2 + 2 * 1 = 12

The part of the rectangle that is not shaded must be 60 - 12 = 48

The probabilty is 48/60 = 4/5 = 0.8 = 80%

GYanggg Apr 15, 2018