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0

1179

4

+502

Express in terms of sin $\theta$ only:

$\frac{cos\theta}{sin\theta}$

Rauhan Dec 22, 2017

edited by Rauhan Dec 22, 2017

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hectictar · Answer 1 · 2017-12-22T09:27:59

$\frac{\pm\sqrt{1-\sin^2\theta}}{\sin\theta}$

*edit*

I don't think that this is correct anymore, but I don't know what the correct answer is.

.

Guest · Answer 2 · 2017-12-22T04:58:58

#1

0

= +, - [sqrt(1 - sin^2(theta))] / sin(theta)

Guest Dec 22, 2017

#2

+502

+1

can u write this equation in the latex thingy so i can understand more clearly

Rauhan Dec 22, 2017

#3

+9488

+2

Best Answer

$\frac{\pm\sqrt{1-\sin^2\theta}}{\sin\theta}$

*edit*

I don't think that this is correct anymore, but I don't know what the correct answer is.

hectictar Dec 22, 2017

edited by hectictar Dec 23, 2017
edited by hectictar Dec 23, 2017

#4

+502

+1

the correct answer is

$\frac{1-sin^2\theta}{sin\theta}$

Rauhan Dec 24, 2017

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