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Express in terms of sin \(\theta \) only:

\(\frac{cos\theta}{sin\theta}\)

\(\frac{\pm\sqrt{1-\sin^2\theta}}{\sin\theta}\)

*edit*

I don't think that this is correct anymore, but I don't know what the correct answer is.

= +, - [sqrt(1 - sin^2(theta))] / sin(theta)

can u write this equation in the latex thingy so i can understand more clearly

the correct answer is

\(\frac{1-sin^2\theta}{sin\theta}\)