Express in terms of sin \(\theta \) only:
\(\frac{cos\theta}{sin\theta}\)
\(\frac{\pm\sqrt{1-\sin^2\theta}}{\sin\theta}\)
*edit*
I don't think that this is correct anymore, but I don't know what the correct answer is.
= +, - [sqrt(1 - sin^2(theta))] / sin(theta)
can u write this equation in the latex thingy so i can understand more clearly
the correct answer is
\(\frac{1-sin^2\theta}{sin\theta}\)