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1206

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+173

Compute (5C1+5C2+5C3) * (6C2+6C3+6C4)

wiskdls May 14, 2018

1⁺⁰ Answers

+4624

+1

Combinations!

${5}\choose{1}$ + ${5}\choose{2}$ + ${5}\choose{3}$ = $5+10+10=25$

${6}\choose{2}$ + ${6}\choose{3}$ + ${6}\choose{4}$ = $15+20+15=50$

Thus, $50*25=\boxed{1250}$

tertre May 14, 2018

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