Compute (5C1+5C2+5C3) * (6C2+6C3+6C4)
Combinations!
\({5}\choose{1} \)+\({5}\choose{2}\)+\({5}\choose{3}\)= \(5+10+10=25\)
\({6}\choose{2}\)+\({6}\choose{3}\)+\({6}\choose{4}\)=\(15+20+15=50\)
Thus, \(50*25=\boxed{1250}\)
