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Compute (5C1+5C2+5C3) * (6C2+6C3+6C4)

wiskdls  May 14, 2018
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Combinations!

\({5}\choose{1} \)+\({5}\choose{2}\)+\({5}\choose{3}\)\(5+10+10=25\)

\({6}\choose{2}\)+\({6}\choose{3}\)+\({6}\choose{4}\)=\(15+20+15=50\)

Thus, \(50*25=\boxed{1250}\)

smileysmiley

tertre  May 14, 2018

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