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A cylindrical can of internal radius 20 cm stands upright on a flat surface. It contains water to a depth of 20 cm. Calculate the rise in the level of the water when a brick of brick of volume 1500cm^{3 } is immersed in the water.

Rauhan Jan 19, 2017

#1**+5 **

Hi Rauhan

A cylindrical can of internal radius 20 cm stands upright on a flat surface. It contains water to a depth of 20 cm. Calculate the rise in the level of the water when a brick of brick of volume 1500cm3 is immersed in the water.

A really important thing to remember is that 1cm^3 holds 1mL of water.

so

a 1500cm^3 brick will displace 1500ml of water.

The original height of the water is irrelavant. Unless the water overflows.

How much height is this?

\(\pi r^2 h=Volume\\ \pi *20^2*h=1500\\ h=\frac{1500}{400\pi}\\ h=\frac{15}{4\pi}\;cm\)

h=1.193662073189215 cm

The water will rise approx 1.2cm

Melody Jan 19, 2017