maths

Let me express this in algebra form. 

Lets put Quail as Q, and Chicken as C.

3C=2Q

3C-210/2Q = 1/3

Lets bring 2Q into 3C.

2Q-210/2Q=1/3

We can use cross multiplication.

6Q-630=2Q

4Q=630

Q=157.5

2Q=315

There are 315 Quail eggs.

But, we want the total number of eggs at the end, so we must find the amount of chicken eggs too.

3C=2Q

3C=315

We want 3C-210.

315-210=105

So the total number of eggs is 105+315=420 eggs at the end.

C : Q = 3 : 2

C - 210 : Q = 1 : 3

${C \over Q} = { 3 \over 2}$

${{C - 210} \over Q} = { 1 \over 3}$

so C = (3/2)Q

${{{3 \over 2}Q - 210} \over Q} = {1 \over 3}$

${{3 \over 2}Q} - 210 = {1 \over 3}Q$

${3 \over 2} - {1 \over 3} = {9 \over 6} - {2 \over 6} = {7 \over 6}$

${7 \over 6}Q = 210$

so Q = 180

So C = 270

now C = 60

so a total of 240