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In the morning, the ratio of the chicken eggs to the quail eggs at the market was 3 : 2. By the evening, 210 chicken eggs were sold, the ratio of the number of chicken eggs to the quail eggs became 1 : 3. How many eggs were at the market in the end?

 Aug 16, 2021
 #1
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Let me express this in algebra form. 

Lets put Quail as Q, and Chicken as C.

3C=2Q

3C-210/2Q = 1/3

Lets bring 2Q into 3C.

2Q-210/2Q=1/3

We can use cross multiplication.

6Q-630=2Q

4Q=630

Q=157.5

2Q=315

There are 315 Quail eggs.

But, we want the total number of eggs at the end, so we must find the amount of chicken eggs too.

3C=2Q

3C=315

We want 3C-210.

315-210=105

So the total number of eggs is 105+315=420 eggs at the end.

 Aug 16, 2021
 #2
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That's the WRONG answer. It's easy to get wrong answers but hard to get correct answers

florianmanteyw  Aug 16, 2021
 #4
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am i correct?

Guest Aug 24, 2021
 #3
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C : Q = 3 : 2

 

C - 210 : Q = 1 : 3

 

 

\({C \over Q} = { 3 \over 2}\)

 

\({{C - 210} \over Q} = { 1 \over 3}\)

 

so C = (3/2)Q

 

\({{{3 \over 2}Q - 210} \over Q} = {1 \over 3}\)

\({{3 \over 2}Q} - 210 = {1 \over 3}Q\)

\({3 \over 2} - {1 \over 3} = {9 \over 6} - {2 \over 6} = {7 \over 6}\)

\({7 \over 6}Q = 210\)

so Q = 180

So C = 270

now C = 60

 

so a total of 240

 Aug 24, 2021

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