Fill in the other coordinate for the line
3x−5y=2
(2,y )
\(\begin{array}{|rcll|} \hline 3x-5y &=& 2 \quad & | \quad x = 2\\ 3\cdot 2-5y &=& 2 \\ 6 - 5y &=& 2 \quad & | \quad \cdot (-1) \\ -6 + 5y &=& -2 \quad & | \quad +6 \\ 5y &=& -2 +6 \\ 5y &=& 4 \quad & | \quad :5 \\ y &=& \frac{4} {5} \\ \hline \end{array} \)
\((2,y ) = (2,\frac{4} {5} ) \)