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The opposite angles in of a cyclic quadrilateral are (3x+10)° and (2x+20)°. Find the angles.

 Nov 24, 2016
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(3x+10)° and (2x+20)°.

 

Since the opposte angles of a cyclic quadrilateral sum to 180°, we have that

 

(3x + 10) + (2x + 20)  = 180   simplify the left side

 

5x + 30   = 180       subtract 30 from each side

 

5x  = 150     divide both sides by 5

 

x =  30

 

So.....the first angle = [ 3(30) + 10 ] = [ 90 + 10 ] = 100°

 

And the second angle = 180 - 100 = 80°

 

 

 

cool cool cool

 Nov 24, 2016

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