Find the solution of the system whose augmented matrix is:
\(\begin{pmatrix} 1 & 2 & 0 & | & 2\\ 2 & 0 & 1 & | & 1\\ 3 & 2 & 1 & | & 3 \end{pmatrix}\)
Let us find the determinant of this system
1 2 0 1 2
2 0 1 2 0
3 2 1 3 2
( 0 + 6 + 0 ) - ( 0 + 2 + 4)
6 - 6 = 0
This indicates that we either have no solutions or infinite solutions
Gretzu, we could solve this with Gaussian elimination, but it seems easier to just use some Algebra
We have
x + 2y = 2 ⇒ 2y = 2 - x (1)
2x + z = 1 ⇒ z = 1 - 2x (2)
3x + 2y + z = 3 (3)
Sub (1) and (2) into (3) and we have that
3x + (2 - x) + (1 - 2x) = 3 simplify
3 = 3
This is always true....so we have infinite solutions
Holding x constant we have the solutions { x, (2 - x) / 2 , 1 - 2x }