The first matrix (A) shows the number of cars and bicycles owned by two families. The second matrix (B) records the wheels and seats for cars and bicycles.

Use a matrix product to find a matrix that gives the number of wheels and seats owned by each family.

A =

Cars | Bicycles | |
---|---|---|

Smith | 2 | 3 |

Jones | 1 | 4 |

B =

Wheels | Seats | |
---|---|---|

Car | 4 | 5 |

Bicycle | 2 | 1 |

(Matrices are in tables as I cant make matrices)

MathsLlama May 10, 2020

#1**+1 **

**The first matrix (A) shows the number of cars and bicycles owned by two families. **

**The second matrix (B) records the wheels and seats for cars and bicycles.**

**Use a matrix product to find a matrix that gives the number of wheels and seats owned by each family.**

\(\begin{array}{|c|c|c|} \hline A & \text{Cars} & \text{ Bicycles } \\ \hline \text{Smith} & 2 & 3 \\ \hline \text{Jones} & 1 & 4 \\ \hline \end{array} \begin{array}{|c|c|c|} \hline B & \text{Wheels} & \text{ Seats } \\ \hline \text{Car} & 4 & 5 \\ \hline \text{Bicycle} & 2 & 1 \\ \hline \end{array}\)

\(\begin{array}{|rcll|} \hline A \times B &=& \left( \begin{array}{cc} 2 & 3 \\ 1 & 4 \\ \end{array}\right) \times \left(\begin{array}{cc} 4 & 5 \\ 2 & 1 \\ \end{array}\right) \\ &=& \left(\begin{array}{cc} 14 & 13 \\ 12 & 9 \\ \end{array}\right) \\ \hline \end{array} \)

\(\begin{array}{|c|c|c|} \hline A\times B & \text{Wheels} & \text{ Seats } \\ \hline \text{Smith} & 14 & 13 \\ \hline \text{Jones} & 12 & 9 \\ \hline \end{array} \)

heureka May 11, 2020