[ -3+b ] - ([ b+a ] - [ 0 ])
2b 2a b2
Sorry about the way I represented the question, hopefully I makes sense though. Thanks!
[ -3+b - ( [ b+a - [ 0 )
2b ] 2a ] b2]
Adding/subtracting like elements inside the parentheses, we have
[ (b + a) - 0 [ b + a
(2a - b^2 ] = 2a - b^2 ]
So....we're left with
[ -3 + b - [ b + a [ -3 + b - b - a [ -3 - a
2b ] 2a - b^2 ] = 2b - 2a + b^2] = 2b - 2a + b^2 ]