+0  
 
0
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1
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[ -3+b  ]   -  ([  b+a  ]  -   [  0  ])

   2b                2a               b2

                          

Sorry about the way I represented the question, hopefully I makes sense though. Thanks!

 Apr 26, 2016
edited by Guest  Apr 26, 2016
edited by Guest  Apr 26, 2016
edited by Guest  Apr 26, 2016
 #1
avatar+130516 
0

[ -3+b     -  (  [  b+a    -   [  0     )

   2b ]               2a ]           b2]

 

Adding/subtracting like elements inside the parentheses, we have

 

[ (b + a)  - 0               [ b + a

  (2a - b^2 ]       =         2a - b^2 ]

 

So....we're left with

 

[ -3 + b    -  [ b + a             [ -3 + b - b - a             [ -3 - a

    2b  ]        2a - b^2 ]  =      2b - 2a + b^2]  =         2b - 2a + b^2 ]

 

 

cool cool cool

 Apr 26, 2016

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