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max value of X

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96pi=24pi+x(4/3pi*27) whats the max value of X?

Guest Jul 31, 2017
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This is the original equation:

$$96\pi = 24\pi+x(\frac{4}{3}\pi*27)$$

We want to solve for x here:

 $$96\pi = 24\pi+x(\frac{4\pi}{3}*27)$$ First, evaluate what is in the parentheses. $$\frac{4\pi}{3}*27$$ $$\frac{4\pi}{3}*27=\frac{4\pi}{3}*\frac{27}{1}=\frac{108\pi}{3}=36\pi$$ Reinsert this back into the original equation. $$96\pi=24\pi+36\pi x$$ Subtract $$24\pi$$ on both sides of the equation. $${72\pi=36\pi x}$$ Divide both sides by the GCF of $$72\pi$$ and $$36\pi x$$. The pi will cancel out and the GCf of 72 and 36 is 36. Therefore, divide both sides by 36*pi. $$\frac{70\pi}{36\pi}=\frac{36\pi x}{36\pi}$$ Simplify both sides of the equation. $$2=x$$ x is already isolated, so we are done!

We're done now! Yes!

TheXSquaredFactor  Jul 31, 2017
edited by TheXSquaredFactor  Jul 31, 2017

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