a ball is thrown vertically upward. after T seconds, its height H (in feet) is given by the function h(t)=44t-16t^2. What is the maximum height the ball will reach?
(I'm not very good at functions... but I think this is correct)
h(t)=44t-16t^2
t=44/32=11/8
h(t)=44(11/8)-16(11/8)^2=121/2-121/4=$\boxed{\frac{121}4}$