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 Let a, b, c, be the numbers 1, 2, 3, in some order. Find the largest possible value of ab + 2ac + 3bc.

 Jun 19, 2024
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avatar+947 
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We want bc to be the biggest, ac to be the second biggest, and ab to be the smallest. 

Obviously, c has to be the biggest number and b has to be the second biggest number. 

 

Thus, c is 3, b is 2, and a is 1. 

We have

\((2*1) + 2(1)(3) + 3(3)(2)\\ 2+6+18\\ 26\)

 

So our answer is 26. 

 

Thanks! :)

 Jun 19, 2024

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