Hey, unsure if I you'll really understand me without a picture but I'll try to explain the question as precise as possible.
So Daniel owns a space where the width is 5 m and the length is 6 m, and he wants to build a roof for it where the central angle at the top has to be 90 degrees, and the question is as following, what are the minimum measurements for the roof to cover his whole space which is 5 m wide and 6 m long?
+37170 OK...I think I got ya.....the roof will have a LARGER area than 6 x 5 = 30 sq m
the 90 degree roof ridge will form a 45 degree angle with the vertical resulting in a 45-45-90 triangle
The TWO legs of the triangle will be equal and = 5/2 or 6/2 depending on exactly how the roof is positioned over the area of the floor
for the 5/2 orientation:
the hypotenuse will be 5/2^2 + 5/2^2 = hyp^2 Hyp = 3.54 EACH SIDE of the roof will be 3.54 x 6m = 21.21 sq m
you will need a left and right side so 2 x 21.21 = 42.42 sq m for this orientation
NOW let's rotate tthe roof 90 degrees, then the legs of the triangle will be 6/2
6/2 ^2 + 6/2 ^2 = hyp^2 hyp = 4.24 the other side of the roof line will be 5 meters and we need two of these
2 x (4.24 x 5) = 42.42 (the same)
SO it does not matter the roof orientation, the minumum area of roof wil be 42.42 sq m
