a Area UNDER the velocity-time graph is the dosplacement of the trains.
train B has the larger area...it has travelled the farthest
train b area = 8 x 5.8 - 1/2(.8)(8) =
Train a area(displacement) = 8 x 5.8 - 1/2 (4.8)(8) =
b determint the equations of the lines for train a and train b.... then train a = train b +9 and solve for t
