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Find the lengths of the medians of the triangle with vertices A(-3,5), B(2,4) and C(-1,-4)

 Jul 19, 2016
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A(x1, y1) B(x2, y2)

MAB=([x1+x2]/2, [y1+y2]/2)

=([-3+2]/2, [5+4]/2)=D(-1/2, 9/2)

dza=sqrt([x2-x1]2+[y2-y1]2)

dCD=sqrt([3/2]2+[17/2]2)=sqrt(9/4+289/2)=sqrt(298/4)=sqrt(298)/2

 

MBC=E(3/2,0)

dAE=sqrt([-3/2]2+52)=sqrt(109/4)=sqrt(109)/2

 

MAC=F(-1, 1/2)

dBF=sqrt(32+[7/2]2)=sqrt([36+49]/4)=sqrt(85)/2

 Aug 2, 2016

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