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# mensuration

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1. if the area of rhombus is 48 cm^2 . and one diagonal is 6cm. find its altitude. i want answer.

​2. NAME A POLYHEDRON THAT HAVE 4  VERTICES 6 FACES NAD 8 EDGES

Mar 13, 2016

#1
+10

Here's (1)

Area of a rhombus =  (1/2) d1*d2 ....where d1, d2 are the diagonals......so  let d1  = 6   and we have

48 =(1/2) 6 *d2

48 = 3 * d2    divide both sides by 3

16 = d2

And since the diagonals bisect each other at right angles, they form two legs of a right triangle.....so...the length of the base = √[8^2 + 3^2]  = √[64 + 9]  = √73

And the area can also be expressed as  a*b  where a is the altitude and b is the base....so we have

48 = a * b

48 = a * √73

altitude  = 48 / √73  = about 5.618  cm   Mar 13, 2016

#1
+10

Here's (1)

Area of a rhombus =  (1/2) d1*d2 ....where d1, d2 are the diagonals......so  let d1  = 6   and we have

48 =(1/2) 6 *d2

48 = 3 * d2    divide both sides by 3

16 = d2

And since the diagonals bisect each other at right angles, they form two legs of a right triangle.....so...the length of the base = √[8^2 + 3^2]  = √[64 + 9]  = √73

And the area can also be expressed as  a*b  where a is the altitude and b is the base....so we have

48 = a * b

48 = a * √73

altitude  = 48 / √73  = about 5.618  cm   CPhill Mar 13, 2016
#2
+5

I believe number 2 is a cube

Mar 13, 2016
edited by SpawnofAngel  Mar 13, 2016