+132 A toy consists of a cylinder of diametre 6 cm 'sandwiched' between a hemisphere and a cone of the same diameter. If the cone is of height 8cm and a cylinder is of height 10cm, what is the volume of the toy.
+9479 radius = diameter / 2
r = 6/2 = 3
volume of toy = volume of hemisphere + volume of cylinder + volume of cone
volume of toy = ( \(\frac12*\frac43*\pi*r^3\) ) + ( \(\pi*r^2*\text{cylinder height}\) ) + ( \(\frac13*\pi*r^2*\text{cone height}\) )
volume of toy = ( \(\frac12*\frac43*\pi*3^3\) ) + ( \(\pi*3^2*10\) ) + ( \(\frac13*\pi*3^2*8\) )
volume of toy = ( \(\frac12*\frac43*\pi*27\) ) + ( \(\pi*9*10\) ) + ( \(\frac13*\pi*9*8\) )
volume of toy = ( \(18\pi\) ) + ( \(90\pi\) ) + ( \(24\pi\) )
volume of toy = 132π cubic centimeters ≈ 414.69 cubic cm
