Here is a pretty hard problem that we all can work together to solve before Christmas
In triangle ABC, the measure of ∠B is 90°, BC=16, and AC=20. Triangle DEF is similar to triangle ABC, where vertices D, E, and F correspond to vertices A, B, and C, respectively, and each side of triangle DEF is
the length of the corresponding side of triangle ABC. What is the value of sinF?
B 16 C
AB = sqrt (20^2 - 16^2) = sqrt ( 400 - 256) = sqrt (144) = 12
ΔABC ≈ ΔDEF
Since the triangles are similar, then sin F = sin C = 12/20 = 3/5