Michaela drops a ball vertically from a height of 80 feet. The peak height after each bounce is half the previous height.

Question

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Michaela drops a ball vertically from a height of 80 feet. The peak height after each bounce is half the previous height.

How far does the ball travel from the time she drops it until it reaches the peak height after the 5th bounce?

155 ft

230 ft

232.5 ft

312.5 ft

i think it is 232.5 ft

jjennylove Mar 18, 2019

ElectricPavlov · Answer 1 · 2019-03-18T09:19:08

Bounce 1 2 3 4 5

80 + 40X2 + 20 x 2 + 10 x 2 + 5 x 2 + 2.5 = 232.5 ft

CPhill · Answer 2 · 2019-03-18T09:34:21

Correct !!!!

The distance is given by

80 + 80[ 1 - (1/2)^4] / [ 1 - 1/2] + 80(1/2)^5 = 232.5