What is the value of s in the equation 4(2s − 1) = 7s + 12? What do I do when I have like terms on both sides of the equation?
\(\begin{array} \\4(2s-1)&=&7s+12&|\text{Expand LHS}\\ 8s-4&=&7s+12&|\text{Subtract 7s from both sides}\\ s-4&=&12&|\text{Add 4 on both sides}\\ s&=&16&|\color{black}\boxed{\color{red}\text{FINISH!}} \end{array}\)
.Thank you so much for your help I just have one question after subtracting seven from both side's you don't have to divide anything just add the 4 to both sides and it will display your S?