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Let (x,y) be an ordered pair of real numbers that satisfies the equation x^2 + y^2 = 14x + 40y. What is the minimum value of x?

 Dec 21, 2020

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Re-arrange this circle equation to standard form  to find the center and the radius

 

x^2 -14x           + y^2 -40y    = 0

(x-7)^2              + (y-20)^2    = 49 + 400

center is   7,20     radius is sqrt 449

minumum x would be     7 - sqrt 449

 Dec 21, 2020
 #1
avatar
+1
Best Answer

Re-arrange this circle equation to standard form  to find the center and the radius

 

x^2 -14x           + y^2 -40y    = 0

(x-7)^2              + (y-20)^2    = 49 + 400

center is   7,20     radius is sqrt 449

minumum x would be     7 - sqrt 449

Guest Dec 21, 2020

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