Let x and y be nonnegative real numbers. If xy = \frac{2}{5}, then find the minimum value of 6x + \frac{3}{5y}.
xy = 2/5
y = 2 / (5x)
6x + 3 / (2 / (5x) ) =
6x + (15/2)x =
(27/2) x
This has no min
+400 
