how to simplify (4 - 8x)(4 + 8x)
and also
factorise Fully
x^2-7x+12
4x^2-25
4x^2-13x+3
6x^3+3x^2+4x+2
The right answer is:
\(\begin{array}{rcl} (4 - 8x)(4 + 8x) &=& \\ &=&4^2 - (8x)^2\\ &=& 16 -64\cdot x^2\\\\ \mathbf{(4 - 8x)(4 + 8x) } & \mathbf{=} & \mathbf{16 -64\cdot x^2} \end{array}\)
First you should learn how to expand double brackets.
So here is a good place to start.
https://www.youtube.com/watch?v=iB3L5csbB4E
Hallo guest
The last one:
The graph
