+0  
 
+5
530
1
avatar+36 

Temperature at midnight is 56°, the high and low temperatures during the day are 71° and 41°. find an equation for the temperature.

Find the times when the temperature is 60°.

What I got:

y = 15sin(pix/12)+56

 

However, the professor wrote f(t)= -15sin(pit/12)+56

Why he got a -15 and i got a +15?

As I know the equation y=Asin(Bx+C) A is positive.

 Dec 9, 2015

Best Answer 

 #1
avatar+128521 
+10

Look at your graph  and your professor's  here :  https://www.desmos.com/calculator/bg0eniwddi

 

Notice that, 6 hours after midnight  - 6AM - your graph reads 71°   while your professor's reads 41°.......this seems  more likely because the coolest temperatures usually occur in the early morning hours

 

Also.....notice that 18 hours after midnight  - at 6PM - your graph reaches its lowest temperature  of 41°  while your professor's hits 71°......this is also more likely as temperatures usually peak around the early evening hours

 

You were close.......note that "A"  can take on  a negative value......!!!!!!!.......it just "flips" the curve when it's negative........

 

 

cool cool cool

 Dec 9, 2015
 #1
avatar+128521 
+10
Best Answer

Look at your graph  and your professor's  here :  https://www.desmos.com/calculator/bg0eniwddi

 

Notice that, 6 hours after midnight  - 6AM - your graph reads 71°   while your professor's reads 41°.......this seems  more likely because the coolest temperatures usually occur in the early morning hours

 

Also.....notice that 18 hours after midnight  - at 6PM - your graph reaches its lowest temperature  of 41°  while your professor's hits 71°......this is also more likely as temperatures usually peak around the early evening hours

 

You were close.......note that "A"  can take on  a negative value......!!!!!!!.......it just "flips" the curve when it's negative........

 

 

cool cool cool

CPhill Dec 9, 2015

3 Online Users