What is the monthly compount interest rate if at the end of 19 months the result is 1.1296?
+118723 I think it is fair to assume that the initial investment was 1 unit of money.
A=P(1+i)n
1.1296=1(1+i)19
1.1296^(1/19)=1+i
i=1.1296^(1/19)-1
$${{\mathtt{1.129\: \!6}}}^{\left({\frac{{\mathtt{1}}}{{\mathtt{19}}}}\right)}{\mathtt{\,-\,}}{\mathtt{1}} = {\mathtt{0.006\: \!434\: \!485\: \!969\: \!525\: \!8}}$$
monthly interest rate is approximately 0.643 %
+118723 I think it is fair to assume that the initial investment was 1 unit of money.
A=P(1+i)n
1.1296=1(1+i)19
1.1296^(1/19)=1+i
i=1.1296^(1/19)-1
$${{\mathtt{1.129\: \!6}}}^{\left({\frac{{\mathtt{1}}}{{\mathtt{19}}}}\right)}{\mathtt{\,-\,}}{\mathtt{1}} = {\mathtt{0.006\: \!434\: \!485\: \!969\: \!525\: \!8}}$$
monthly interest rate is approximately 0.643 %
