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15 fair 6-sided dice are tossed. What is the probability that you will get a total sum of 53?

 Jun 5, 2016
 #1
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[n + n^2 + n^3 + n^4 + n^5 + n^6]^15.

The expansion of this generating series will give terms from n^90 to n^15. You simply calculate the coeffficient of n^53 =27,981,391,815. Then 27,981,391,815 / 6^15=0.059511.... x 100 =5.9511%, which is the exact probability.

 Jun 6, 2016
 #2
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Why do you think that this is true?  It makes no sense to me.

 Jun 6, 2016
 #3
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http://www.wolframalpha.com/input/?i=15+tosses+of+6-sided+dice,+total+of+53

 Jun 6, 2016

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