Ok, a new question, d^-3 for d= -2 If im correct its -1/8, but im still not sure
K thanks :)
OK Finally back :)
\(\quad d^{-3} \text{ when } d= -2\\ =(-2)^{-3}\\ =\dfrac{1}{(-2)^3}\\ =\dfrac{1}{-8}\\ =-\dfrac{1}{8}\)
You are correct :)
+36 
