+0

0
82
1

Assuming that x doesn't equal to -3 simplify ((8x-4)/(x+3))/((12x-20)/(2x-6))

Guest Oct 4, 2017
Sort:

#1
+1493
+1

To simplify this monstrosity $$\frac{\frac{8x-4}{x+3}}{\frac{12x-20}{2x-6}}$$, we must eliminate the inner fractions.

 $$\frac{\frac{8x-4}{x+3}}{\frac{12x-20}{2x-6}}*\frac{\frac{2x-6}{12x-20}}{\frac{2x-6}{12x-20}}$$ Multiply by the reciprocal of the denominator to eliminate the fraction in a fraction. This may look complicated, but we are actually multiplying the fraction by 1, which does not affect its value. $$\frac{8x-4}{x+3}*\frac{2x-6}{12x-20}$$ Now, multiply the fractions together. Let's start with the numerator. $$(8x-4)(2x-6)=16x^2-48x-8x+24=16x^2-56x+24$$ Do the same with the denominator. $$(x+3)(12x-20)=12x^2-20x+36x-60=12x^2+16x-60$$ Now, combine them together. $$\frac{16x^2-56x+24}{12x^2+16x-60}$$ Both the numerator and denominator both have a GCF of 4. $$\frac{4x^2-14x+6}{3x^2+4x-15}$$
TheXSquaredFactor  Oct 4, 2017

### 12 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details