Assuming that x doesn't equal to -3 simplify ((8x-4)/(x+3))/((12x-20)/(2x-6))

Guest Oct 4, 2017

1+0 Answers


To simplify this monstrosity \(\frac{\frac{8x-4}{x+3}}{\frac{12x-20}{2x-6}}\), we must eliminate the inner fractions.


\(\frac{\frac{8x-4}{x+3}}{\frac{12x-20}{2x-6}}*\frac{\frac{2x-6}{12x-20}}{\frac{2x-6}{12x-20}}\) Multiply by the reciprocal of the denominator to eliminate the fraction in a fraction. This may look complicated, but we are actually multiplying the fraction by 1, which does not affect its value. 
\(\frac{8x-4}{x+3}*\frac{2x-6}{12x-20}\) Now, multiply the fractions together. Let's start with the numerator.
\((8x-4)(2x-6)=16x^2-48x-8x+24=16x^2-56x+24\) Do the same with the denominator.
\((x+3)(12x-20)=12x^2-20x+36x-60=12x^2+16x-60\) Now, combine them together.
\(\frac{16x^2-56x+24}{12x^2+16x-60}\) Both the numerator and denominator both have a GCF of 4.
TheXSquaredFactor  Oct 4, 2017

6 Online Users

New Privacy Policy (May 2018)

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see cookie policy and privacy policy.