Hard to figure out lol

y=x^2−3x+7

y=3x−2

What is the y-coordinate of the solution?

Thanks a million!! :)

PhoenixForever Feb 25, 2019

#1**+2 **

y=x^2−3x+7

y=3x−2

Set yhe y's equal and we have that

x^2 - 3x + 7 = 3x - 2 subtract 3x / add 2 from/to both sides

x^2 - 6x + 9 = 0 factor

(x - 3)^2 = 0 which implies that x = 3

So.......plug 3 into either function and we get that y = 3(3) - 2 = 7

CPhill Feb 25, 2019

#2**+2 **

Set it so that \(x^2-3x+7=3x-2\) .

Now bring over to the left side: \(x^2-6x+9=0\)

We can find out that \(x=3\).

Now plug it in to \(y=3x-2 => y=3(3)-2 => y=7\)

Therefore, the y-coordinate is 7.

You are very welcome!

:P

CoolStuffYT Feb 25, 2019