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A point is chosen at random on the coordinate plane such that both of its coordinates are between 0 and 2. What is the probability that the point is less than 1 unit from the origin?
 Aug 8, 2016

Best Answer 

 #1
avatar+130511 
+10

We can construct a square with its  bottom left edge at (0,0), its top left edge at (0,2), its top right edge at (2,2)  and its bottom right edge at (2,0)....all the points within this square will have x, y coordinates between 0 and 2

So......the total area of this square  = 4 units^2

 

And the probability that a point in this square lies exactly 1  unit from the origin will be the collection of points in the quarter circle contained in this square with a radius of 1 unit......and the area of this circle = (1/4)pi (1)^2   = pi/4

 

So....the probability that any chosen point lies less than 1 unit form the origin will be a little less than :

 

[ pi/ 4] / 4  = pi / 16  ≈  .196

 

Here's a picture of the situation :

 

 

cool cool cool

 Aug 8, 2016
 #1
avatar+130511 
+10
Best Answer

We can construct a square with its  bottom left edge at (0,0), its top left edge at (0,2), its top right edge at (2,2)  and its bottom right edge at (2,0)....all the points within this square will have x, y coordinates between 0 and 2

So......the total area of this square  = 4 units^2

 

And the probability that a point in this square lies exactly 1  unit from the origin will be the collection of points in the quarter circle contained in this square with a radius of 1 unit......and the area of this circle = (1/4)pi (1)^2   = pi/4

 

So....the probability that any chosen point lies less than 1 unit form the origin will be a little less than :

 

[ pi/ 4] / 4  = pi / 16  ≈  .196

 

Here's a picture of the situation :

 

 

cool cool cool

CPhill Aug 8, 2016

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