Find sin A if cos A = 0.4
I. Quadrant:
\(\sin{(A)} = + \sqrt{1-\cos^2{(A)}}\\ \sin{(A)} = + \sqrt{1-0.4^2}\\ \sin{(A)} = 0.91651513899 \)
IV. Quadrant:
\(\sin{(A)} = - \sqrt{1-\cos^2{(A)}}\\ \sin{(A)} = - \sqrt{1-0.4^2}\\ \sin{(A)} = -0.91651513899\)
Hello heureka!
It is "top",
how you represent the trigonometric relationships.
I myself have not considered the arc cos 0.4 is ambiguous,
and your explanation with the unit circle is very obvious.
In my answer is wrong A = 0.916515138992,
correct is sin A = 0.916515138992
Greetings asinus :- )
!