+0  
 
+1
654
1
avatar+956 

 

Thanks!

 May 2, 2018
 #1
avatar+26367 
+2

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\(\displaystyle \vec{BX} = \frac{ \vec{BC}+\vec{CD} }{2}\\ \displaystyle \vec{BX} = -\frac{ (\vec{DA}+\vec{AB}) }{2}\)

 

laugh

 May 3, 2018
edited by heureka  May 3, 2018

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