+166 The water tank in the diagram below is in the shape of an inverted right circular cone. The radius of its base is 16 feet, and its height is 96 feet. The water in the tank is 25% of the tank's capacity. The height of the water in the tank can be written in the form \(a\sqrt[3]{b}\) , where and a and b are positive integers and b is not divisible by a perfect cube greater than 1. What is a+b?
ABCD is a regular tetrahedron (right triangular pyramid). If M is the midpoint of CD, then what is tan(angAMB)?
+129852 Here's the first one
Call the height of the water in the tank, H
And ......using similar triangles, we can express the radius, R, at this point thusly :
16 / 96 = R / H
1/6 = R/H
H/6 = R
Now when the tank is 25% full, it will hold
(1/4) (1/3) pi 16^2 * 96 = 2048 pi ft^3
So....to find the height, we have
2048 pi = (1/3) pi (H/6)^2 * H divide out pi, multiply both sides by 3
6144 = H^3 / 36 multiply both sides by 36
221184 = H^3
Take the cube root of both sides
483√2 = H
So
a + b = 48 + 2 = 50
+166 There was no picture. It is a regular tetrahedron, so any orientation will be fine.
