The easiest way to solve this triangle (find the measures of the angles A, B, and C) is
(1) Find cos-1 .28 = B.
(2) Then find A = (180º-B).
(1) Find cos-1 .96 = B.
(2) Then find A = (90º-B).
(1) Find cos-1 .96 = A.
(2) Then find B = (180º-A).
(1) Find sin-1 .28 = A.
(2) Then find B = (90º-A).
+130511 Mmmmm....."D" would be the closest to being correct.....because the side opposite angle A < the side opposite angle B, angle A is < 45 degrees and Angle B is > 45 degrees.......except that we would need to use the Law of Sines first and then apply the sin-1 to find A...thusly .....
sin 90/25 = sin A /7
7/25 = sin A
Sin-1(7/25) =Sin-1(.28) = A = about 16 degrees
And to prove that this is correct....use the Law of Sines again to find angle B =
sin90/25 = sin B /24
(24/25) = sin B
Sin-1(24/25) = Sin-1(.96) = B = about 74 degrees
So A + B = 90 (as they should)
+130511 Mmmmm....."D" would be the closest to being correct.....because the side opposite angle A < the side opposite angle B, angle A is < 45 degrees and Angle B is > 45 degrees.......except that we would need to use the Law of Sines first and then apply the sin-1 to find A...thusly .....
sin 90/25 = sin A /7
7/25 = sin A
Sin-1(7/25) =Sin-1(.28) = A = about 16 degrees
And to prove that this is correct....use the Law of Sines again to find angle B =
sin90/25 = sin B /24
(24/25) = sin B
Sin-1(24/25) = Sin-1(.96) = B = about 74 degrees
So A + B = 90 (as they should)
