+212 What is the equation of the circle in general form?
A. x2+y2−4x−2y−2=0
B. x2+y2+4x+2y−44=0
C. x2+y2−4x−2y−44=0
D. x2+y2+4x+2y−2=0
+128400 The center is ( -2, -1) and the radius is 7
So....using (x - h)^2 + ( y - k)^2 = r^2 where (h , k) is the center and r is the radius, we have
( x - -2)^2 + ( y - - 1)^2 = 7^2
(x + 2) ^2 + (y + 1)^2 = 49 expand and simplify
x^2 + 4x + 4 + y^2 + 2y + 1 = 49
x^2 + y^2 + 4x + 2y + 5 = 49 subtract 49 from both sides
x^2 + y^2 + 4x + 2y - 44 = 0 ⇒ Answer "B"
