(n^2-1)/(2n²-7n-4) excluded value?

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Guest Apr 16, 2015

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Best Answer

The only "excluded" values are those that make the denominator = 0

So we have

2n^2 - 7n - 4 = 0 factor

(2n +1)(n - 4) = 0 and setting both factors to 0, we find that the "excluded" values are n = -1/2 and n = 4

CPhill Apr 16, 2015

CPhill · Answer 1 · 2015-04-16T05:24:29

The only "excluded" values are those that make the denominator = 0

So we have

2n^2 - 7n - 4 = 0 factor

(2n +1)(n - 4) = 0 and setting both factors to 0, we find that the "excluded" values are n = -1/2 and n = 4