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# N Choose K doesn't make sense?

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10
+189

Can someone explain it plz

May 1, 2020

#1
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To calculate the number of happening of an event, N chooses K tool is used. N is the sum of data and K is the number that we chose from the sum of data.

The formula for N choose K formula is

:\(C(n, k)= n!/[k!(n-k)!] \)Where,
n is the total number
k is the number of selected item

Solved Examples

Question 1: How many ways to draw exactly 6 cards from a pack of 10 cards?

Solution:

From the question, it is clear that,
N = 10
N = 6

So the formula for n choose k is,\(C(n, k)= n!/[k!(n-k)!] 610C=10!6!(10−6)!=362880017280 \)= 210

So, there are 210 ways of drawing 6 cards in a pack of 10.

This formula and topic is very useful in solving various types of problems I recommend that you you practice this topic until you feel like you can solve and N choose K question.

Here to help

:D

May 1, 2020
#2
+189
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So then whats..

0 choose 0

1 choose 1

-1 choose 1

SoggyPerson  May 1, 2020
#3
+656
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I belive it would be

0 choose 0 = 1

1 choose 1 = 1

LuckyDucky  May 1, 2020
edited by LuckyDucky  May 1, 2020
#5
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-1 choose 1 is impossible, it is not -1.

HELPMEEEEEEEEEEEEE  May 1, 2020
#7
+189
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so undefinded?

SoggyPerson  May 1, 2020
#10
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Yeah, its undefined.

HELPMEEEEEEEEEEEEE  May 1, 2020
#4
+928
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Anything choose 0 is 1, Anything choose 1 is the number i.e. 1 choose 1 is 1, 2 choose 1 is 2, 3 choose 1 is 3 and so on. You can't use negative numbers is combinatorics.

May 1, 2020
#6
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Thanks for adding to my growing knowledge of new math!

LuckyDucky  May 1, 2020
#8
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Here's proof of LuckyDucky's answer  of 0 choose 0

C(0,0)  =

0!                    1                1

__________  =   _____   =  _____   =  1

(0 - 0)! * 0!           0! * 0!        1  * 1

There's only one way to do this.....forget about it   !!!!

May 1, 2020
#9
+656
+1

Wow, that reasoning blows my mind (JK) its very well said!

Now I have logic to back up my answer.

:D

LuckyDucky  May 1, 2020