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whats the derivative of 4x^3 + 8x^6

 Nov 2, 2016
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Possible derivation:
d/dx(4 x^3+8 x^6)
Differentiate the sum term by term and factor out constants:
 = 4 (d/dx(x^3))+8 (d/dx(x^6))
Use the power rule, d/dx(x^n) = n x^(n-1), where n = 3: d/dx(x^3) = 3 x^2:
 = 8 (d/dx(x^6))+4 3 x^2
Simplify the expression:
 = 12 x^2+8 (d/dx(x^6))
Use the power rule, d/dx(x^n) = n x^(n-1), where n = 6: d/dx(x^6) = 6 x^5:
 = 12 x^2+8 6 x^5
Simplify the expression:
Answer: |= 12x^2 + 48x^5

 Nov 2, 2016

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