+0  
 
-1
132
3
avatar+128 

In the diagram below we have QR is parallel to ST, PQ=8, QS=6, and PT=10.5

Find PR

https://latex.artofproblemsolving.com/7/0/2/70221f74557d9f47f65c187cf798e80474ed0974.png

 Oct 8, 2019
 #1
avatar+999 
0

Please don't post AoPS questions (or at least spam them).

Use the Message Board, or ask a friend! Only if you really need the answer, ask for hints.

 

PQR and PST are similar. PQ + QS = 14, and PQ = 8, so PQ is 8/14, or 4/7, the length of PS.

Same proportion for PT. PT is 10.5, and PR is 4/7 of that length. Can you find out from here?

 Oct 8, 2019
 #3
avatar+2547 
0

Yes you must be taking an AoPS class! How lucky of you Saketh :D

 

 

Just try the problems they give you first, and try your best. And maybe post your attempted solution with the question.

 

 

 

*You will get smarter (trust me)*

CalculatorUser  Oct 9, 2019
 #2
avatar+106539 
+2

QR  splits the sides PS and PT proportionally.....

 

So

 

PQ / PR  =  PS / PT

 

PQ / PR  = [ PQ + QS] / PT

 

8/ PR  =  [ 8+ 6 ]  / 10.5

 

8 /PR  = 14/10.5

 

PR / 8  =  10.5 / 14

 

PR  =  8 (10.5) /14  =  6

 

cool cool cool

 Oct 9, 2019

10 Online Users

avatar
avatar
avatar