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Point $X$ is on $\overline{AC}$ such that $AX = 4\cdot CX = 12$. We know $\angle ABC = \angle BXA = 90^\circ.$ What is $BX$?

https://latex.artofproblemsolving.com/d/f/9/df9066fdcb6254b17f9af91efe50d1c466810587.png

 Oct 22, 2019
 #1
avatar+118 
+4

Please do not post solutions to this problem.  This is a homework problem, and the original poster is trying to cheat.

 Oct 22, 2019
edited by wonderman  Oct 22, 2019
 #2
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Wonderwoman, please stop abusing other's rights for asking for help. You cannot assume that asking for help is cheating.

Guest Oct 27, 2019
 #3
avatar+105634 
0

Wonderman is a pain BUT anybody who posts a question like that is in my veiw only interested in the quickest path to the answer.

i.e. they have the intention of cheating.

 

Sakath cannot even be bothered to present the question properly therefore I conclude he/she cannot be bothered to learn from any answer either.

Melody  Oct 27, 2019
 #4
avatar+54 
-2

Nobody likes wonderman

Leaded  Oct 28, 2019

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