Given f(x)=2x^2−3 and g(x)=x+4 .
What is (fg)(x) ?
−2x^2+x+7
2x^3−12
2x^3+8x^2−3x−12
2x^2+x+1
(fg)(x) = f(x) * g(x) =
(2x^2 - 3) ( x + 4) =
2x^3 + 8x^2 - 3x - 12
+491 
