Baker Yeo sold 120 buns in the morning and 40% of the remaining buns in the afternoon. The number of buns left was 1/3 of the number of buns he had baked. How many buns did he sell in the afternoon?
We can write an equation to solve the problem. Let's let x be the total number of buns he made.
Using the problem, we have the equation
\(\frac{60}{100}(x-120) = 1/3x\)
Solving this equation for x, we find that
\(x=270\)
This means in the afternoon, he sold \(\frac{60}{100}(150) = 90\)
Thus, he sold 90 buns.
So 90 is our answer.
Thanks! :)