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I have a question and don’t know how to answer it. 

 

A rectangle has a base of 6x+7 and a height of 7. The area of the rectangle is 133in^2. Solve for the missing sides.

 

Help would be greatly appreciated

 Aug 17, 2018

Best Answer 

 #1
avatar+26367 
+3

A rectangle has a base of 6x+7 and a height of 7. The area of the rectangle is 133in^2.

Solve for the missing sides.

 

\(\begin{array}{|rcll|} \hline A &=& \text{base} \times \text{height} \\ A &=&(6x+7) \times 7 \quad & | \quad A =133\ \text{in}^2 \\ 133 &=&(6x+7) \times 7 \quad & | \quad :7 \\ 19 &=& 6x+7 \\ \mathbf{6x+7} & \mathbf{=} & \mathbf{19} \\ \hline \end{array}\)

 

The missing side is 19.

 

laugh

 Aug 17, 2018
edited by heureka  Aug 17, 2018
 #1
avatar+26367 
+3
Best Answer

A rectangle has a base of 6x+7 and a height of 7. The area of the rectangle is 133in^2.

Solve for the missing sides.

 

\(\begin{array}{|rcll|} \hline A &=& \text{base} \times \text{height} \\ A &=&(6x+7) \times 7 \quad & | \quad A =133\ \text{in}^2 \\ 133 &=&(6x+7) \times 7 \quad & | \quad :7 \\ 19 &=& 6x+7 \\ \mathbf{6x+7} & \mathbf{=} & \mathbf{19} \\ \hline \end{array}\)

 

The missing side is 19.

 

laugh

heureka Aug 17, 2018
edited by heureka  Aug 17, 2018

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