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# Need help asap!! Plz and ty!

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A train slows from a speed of 40 m/sec to a speed of 30 m/sec in 1500 m. What is its acceleration?

I tried to solve this but I can't get the right formula >.<

Sep 20, 2018

### 2+0 Answers

#1
+101871
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I'm not a Physics expert, but  I believe we need this equation, RP

VF^2  =VI^2  + 2 * a * d

VF  = 30m/s

VI = 40m/s

d  = the displacement  [ how far it moves]....so we have

a = acceleration  (in m/s^2) = ???

30^2  = 40^2  + 2 * a (1500)

900  =  1600 + 3000a    subtract 1600 from both sides

-700  = 3000a     divide  both sides by  3000

-700 / 3000  = a   = -7/30 m/s^2 ≈ -0.233 m/s^2  [ this makes sense....we are  decelerating !!! ]

Sep 20, 2018
#2
+2448
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Thank you so much!!

RainbowPanda  Sep 20, 2018