Need help asap

Let P be the point on Xy such that ZP is parallel to XW.  Then angle PZX = angle ZXW = 105, so angle YXZ = 105 - 141 = 9.  Then angle YZX = 141 - 32 = 109, so angle YXZ = 109 - 2*43 = 23 degrees.

In trapezoid WXYZ, line XY is parallel to line WZ, angle WXZ=105, angle W=43, and angle Y=141. Find YXZ, in degree.

For some reason, I misunderstood this question.

The correct answer is::::              angle YXZ = 32º