need help ASAP

 

1.    angle ADC = angle ADB                                              AD is perpendicular to BC (given) so both are 90^o

 

2.    side AD = side AD                                                       equals itself  

 

3.    angle CAD = angle BAD                                              AD bisects angle CAB (given) so each half is equal 

 

4.    therefore triangle ADC congruent to triangle ADB       angle-side-angle theorem   

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